4x(3x+1)-3(4x^2-4x+1)=

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Solution for 4x(3x+1)-3(4x^2-4x+1)= equation:


Simplifying
4x(3x + 1) + -3(4x2 + -4x + 1) = 0

Reorder the terms:
4x(1 + 3x) + -3(4x2 + -4x + 1) = 0
(1 * 4x + 3x * 4x) + -3(4x2 + -4x + 1) = 0
(4x + 12x2) + -3(4x2 + -4x + 1) = 0

Reorder the terms:
4x + 12x2 + -3(1 + -4x + 4x2) = 0
4x + 12x2 + (1 * -3 + -4x * -3 + 4x2 * -3) = 0
4x + 12x2 + (-3 + 12x + -12x2) = 0

Reorder the terms:
-3 + 4x + 12x + 12x2 + -12x2 = 0

Combine like terms: 4x + 12x = 16x
-3 + 16x + 12x2 + -12x2 = 0

Combine like terms: 12x2 + -12x2 = 0
-3 + 16x + 0 = 0
-3 + 16x = 0

Solving
-3 + 16x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 16x = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 16x = 0 + 3
16x = 0 + 3

Combine like terms: 0 + 3 = 3
16x = 3

Divide each side by '16'.
x = 0.1875

Simplifying
x = 0.1875

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